Optimal. Leaf size=83 \[ \frac {45 \sin (c+d x)}{512 d (5-3 \cos (c+d x))}+\frac {3 \sin (c+d x)}{32 d (5-3 \cos (c+d x))^2}+\frac {59 \tan ^{-1}\left (\frac {\sin (c+d x)}{3-\cos (c+d x)}\right )}{1024 d}+\frac {59 x}{2048} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.06, antiderivative size = 83, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {2664, 2754, 12, 2657} \[ \frac {45 \sin (c+d x)}{512 d (5-3 \cos (c+d x))}+\frac {3 \sin (c+d x)}{32 d (5-3 \cos (c+d x))^2}+\frac {59 \tan ^{-1}\left (\frac {\sin (c+d x)}{3-\cos (c+d x)}\right )}{1024 d}+\frac {59 x}{2048} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 12
Rule 2657
Rule 2664
Rule 2754
Rubi steps
\begin {align*} \int \frac {1}{(5-3 \cos (c+d x))^3} \, dx &=\frac {3 \sin (c+d x)}{32 d (5-3 \cos (c+d x))^2}-\frac {1}{32} \int \frac {-10-3 \cos (c+d x)}{(5-3 \cos (c+d x))^2} \, dx\\ &=\frac {3 \sin (c+d x)}{32 d (5-3 \cos (c+d x))^2}+\frac {45 \sin (c+d x)}{512 d (5-3 \cos (c+d x))}+\frac {1}{512} \int \frac {59}{5-3 \cos (c+d x)} \, dx\\ &=\frac {3 \sin (c+d x)}{32 d (5-3 \cos (c+d x))^2}+\frac {45 \sin (c+d x)}{512 d (5-3 \cos (c+d x))}+\frac {59}{512} \int \frac {1}{5-3 \cos (c+d x)} \, dx\\ &=\frac {59 x}{2048}+\frac {59 \tan ^{-1}\left (\frac {\sin (c+d x)}{3-\cos (c+d x)}\right )}{1024 d}+\frac {3 \sin (c+d x)}{32 d (5-3 \cos (c+d x))^2}+\frac {45 \sin (c+d x)}{512 d (5-3 \cos (c+d x))}\\ \end {align*}
________________________________________________________________________________________
Mathematica [A] time = 0.14, size = 65, normalized size = 0.78 \[ \frac {546 \sin (c+d x)-135 \sin (2 (c+d x))+59 (5-3 \cos (c+d x))^2 \tan ^{-1}\left (2 \tan \left (\frac {1}{2} (c+d x)\right )\right )}{1024 d (5-3 \cos (c+d x))^2} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
fricas [A] time = 0.64, size = 90, normalized size = 1.08 \[ -\frac {59 \, {\left (9 \, \cos \left (d x + c\right )^{2} - 30 \, \cos \left (d x + c\right ) + 25\right )} \arctan \left (\frac {5 \, \cos \left (d x + c\right ) - 3}{4 \, \sin \left (d x + c\right )}\right ) + 12 \, {\left (45 \, \cos \left (d x + c\right ) - 91\right )} \sin \left (d x + c\right )}{2048 \, {\left (9 \, d \cos \left (d x + c\right )^{2} - 30 \, d \cos \left (d x + c\right ) + 25 \, d\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
giac [A] time = 0.43, size = 77, normalized size = 0.93 \[ \frac {59 \, d x + 59 \, c + \frac {12 \, {\left (68 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 23 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (4 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{2}} - 118 \, \arctan \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) - 3}\right )}{2048 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maple [A] time = 0.03, size = 83, normalized size = 1.00 \[ \frac {51 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{128 d \left (4 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+1\right )^{2}}+\frac {69 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{512 d \left (4 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+1\right )^{2}}+\frac {59 \arctan \left (2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{1024 d} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maxima [A] time = 1.29, size = 112, normalized size = 1.35 \[ \frac {\frac {6 \, {\left (\frac {23 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {68 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}}\right )}}{\frac {8 \, \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {16 \, \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + 1} + 59 \, \arctan \left (\frac {2 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{1024 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
mupad [B] time = 0.37, size = 95, normalized size = 1.14 \[ \frac {59\,\mathrm {atan}\left (2\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{1024\,d}-\frac {59\,\left (\mathrm {atan}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )-\frac {d\,x}{2}\right )}{1024\,d}+\frac {\frac {51\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{2048}+\frac {69\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{8192}}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{2}+\frac {1}{16}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
sympy [A] time = 2.80, size = 364, normalized size = 4.39 \[ \begin {cases} \frac {x}{\left (5 - 3 \cosh {\left (2 \operatorname {atanh}{\left (\frac {1}{2} \right )} \right )}\right )^{3}} & \text {for}\: c = - d x - 2 i \operatorname {atanh}{\left (\frac {1}{2} \right )} \vee c = - d x + 2 i \operatorname {atanh}{\left (\frac {1}{2} \right )} \\\frac {x}{\left (5 - 3 \cos {\relax (c )}\right )^{3}} & \text {for}\: d = 0 \\\frac {944 \left (\operatorname {atan}{\left (2 \tan {\left (\frac {c}{2} + \frac {d x}{2} \right )} \right )} + \pi \left \lfloor {\frac {\frac {c}{2} + \frac {d x}{2} - \frac {\pi }{2}}{\pi }}\right \rfloor \right ) \tan ^{4}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{16384 d \tan ^{4}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 8192 d \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 1024 d} + \frac {472 \left (\operatorname {atan}{\left (2 \tan {\left (\frac {c}{2} + \frac {d x}{2} \right )} \right )} + \pi \left \lfloor {\frac {\frac {c}{2} + \frac {d x}{2} - \frac {\pi }{2}}{\pi }}\right \rfloor \right ) \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{16384 d \tan ^{4}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 8192 d \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 1024 d} + \frac {59 \left (\operatorname {atan}{\left (2 \tan {\left (\frac {c}{2} + \frac {d x}{2} \right )} \right )} + \pi \left \lfloor {\frac {\frac {c}{2} + \frac {d x}{2} - \frac {\pi }{2}}{\pi }}\right \rfloor \right )}{16384 d \tan ^{4}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 8192 d \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 1024 d} + \frac {408 \tan ^{3}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{16384 d \tan ^{4}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 8192 d \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 1024 d} + \frac {138 \tan {\left (\frac {c}{2} + \frac {d x}{2} \right )}}{16384 d \tan ^{4}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 8192 d \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 1024 d} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________